The amplitude of a particle executing S.H.M. with frequency of 60 Hz is 0.01m. The maximum value of the acceleration of the particle is
A
144 π 2 m/sec 2
B
144m/sec 2
C
m/sec 2
D
288 π 2 m/sec 2
Text Solution
Verified by ExpertsThe correct answer is:
A
Maximum acceleration = aꞷ 2 = a x 4 π 2 n 2
= a ꞷ 2 = a x 4 π 2 n 2
= 0.01 x 4 ( π ) 2 x (60) 2 = 144 π 2 m/sec 2
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